Suppose you have taken a dilute solution of o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The total volume of $100$ drops is $V_{total} = 100 	imes \frac{4}{3} \pi r^3$.Given $r = \left(\frac{3}{40 \pi}ight)^{1/3} 	imes 10^{-3} \, c

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(B) The total volume of $100$ drops is $V_{total} = 100 	imes \frac{4}{3} \pi r^3$.Given $r = \left(\frac{3}{40 \pi}ight)^{1/3} 	imes 10^{-3} \, cm$,so $r^3 = \frac{3}{40 \pi} 	imes 10^{-9} \, cm^3$.$V_{total} = 100 	imes \frac{4}{3} \pi 	imes \frac{3}{40 \pi} 	imes 10^{-9} = 10^{-8} \, cm^3$.The thickness of the film $t_T$ is given by $Area 	imes t_T = V_{total}$.$4 \, cm^2 	imes t_T = 10^{-8} \, cm^3 \implies t_T = 0.25 	imes 10^{-8} = 25 	imes 10^{-10} \, cm$.Converting to meters: $t_T = 25 	imes 10^{-12} \, m$.The concentration of oleic acid is $0.01$,so the thickness of the oleic acid layer $t_0 = 0.01 	imes t_T$.$t_0 = 0.01 	imes 25 	imes 10^{-12} \, m = 25 	imes 10^{-14} \, m$.Comparing with $x 	imes 10^{-14} \, m$,we get $x = 25$.

Similar Questions

$A$ far-off planet is estimated to be at a distance $D$ from the Earth. If its diametrically opposite extremes subtend an angle $\theta$ at an observatory situated on the Earth,the approximate diameter of the planet is .............

Which method is used in the modern era to measure the distance of a nearby planet from the Earth?

The angle subtended by a plate of diameter $2 \, cm$ at a distance of $1000 \, cm$ from the eye is ..... (in $^\circ$)

In an experiment, a set of readings are obtained: $1.24 \ mm, 1.25 \ mm, 1.23 \ mm, 1.21 \ mm$. The expected least count of the instrument used in recording these readings is . . . . . . $mm$.

Accuracy of measurement of a physical quantity depends on which factors?

Vedclass Test Series

Exam Paper Generator

Online Exam Module